PHP Error: Warning – mysqli_fetch_array() expects the first parameter to be a mysqli_result; however, a resource was provided instead.

This error message indicates that the issue is related to the mysqli_fetch_array() function.

Specifically, the first expected parameter of this function is a mysqli_result object; however, the actual argument passed to it is a resource. This may indicate an issue with the database query.

To resolve this issue, you may need to check your database connection settings and ensure that your query is correctly written. You can also try using the mysqli_error() function to gain a better understanding of the error message and facilitate debugging.

Here is an example of code using the `mysqli::error()` function:

// 执行查询
$result = mysqli_query($connection, $query);

// 检查错误
if (!$result) {
    // 如果出现错误，则打印错误消息
    echo "错误: " . mysqli_error($connection);
}

// 获取数据
while ($row = mysqli_fetch_array($result)) {
    // 对数据进行操作
}

By using this code, you should be able to identify and fix any errors that are causing parameter-related issues with the mysqli_fetch_array() function.